Question

When H2O and CO react at 976°C, the products are CO2 and H2. The equilibrium constant (in terms of equilibrium concentrations of reactants and products) for the reaction below is 0.65 at 976°C. CO(g) + H2O(g) equilibrium reaction arrow CO2(g) + H2(g) If the following concentrations are measured after the reaction reaches equilibrium, what is the concentration of CO(g) in the equilibrated mixture? M Component Measured equilibrium concentration H2O(g) 0.752 M CO2(g) 0.134 M H2(g) 3.36 M

Answer 1

The concentration of CO (g)in equilibrium is 0,921 M

Step-by-step explanation:

The global reaction is:

H₂O (g) + CO (g) ⇄ CO₂ (g) + H₂ (g) With k = 0,65

The equation of equilibrium is:

k =
`([Products])/([Reactants])`

k =
`([H_2][CO_2])/([H_2O][CO])`

Replacing:

0,65 =
`([3,36][0,134])/([0,752][CO])`

Thus, [CO] = 0,921 M

I hope it helps!