Answer:
x=5+√17 or 5-√17
Explanation:
Given the equation x²-10x+25=17 we first make the equation to be in the form
ax²+bx+c=0.
Therefore, we cross 17 to the other side.
x²-10x+25-17=0
x²-10x+8=0
If we substitute the coefficients in the quadratic formula we get:
x=(-b±
)/2a
=(10±
)/(2×1)
x=5+√17 or 5-√17