Answer:
a) 0.1600
b) 0.3654
Explanation:
a) The samples are independents, so:
P(O1∩O2)=P(O1).P(O2)=0.40*0.40=0.1600
b) P(A1∩A2)+P(B1∩B2)+P(AB1∩AB2)+P(O1∩O2)=
P(A1).P(A2)+P(B1).P(B2)+P(AB1).P(AB2)+P(O1).P(O2)=
0.43^2+0.14^2+0.03^2+0.4^2=0.3654
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