Question

Jane, Kindra, and Joyce have old coin collections. Jane has 3 times as many coins as Joyce. Kindra has 2 more than twice the number Joyce has. Together they have 56 old coins. How many coins does each of them have?

Answer 1

Jane has 27 coins, Kindra has 20 coins and Joyce has 9 coins.

Explanation:

Let Joyce's number of old coins be 1 unit / base unit.

Therefore, Jane has 3u coins and Kindra has 2u + 2 coins.

Total = 1u + 3u + 2u + 2 = 6u + 2

6u + 2 = 56

6u = 54

1u = 9

Joyce has 9 coins.

Jane = 3 x 9 = 27

Jane has 27 coins.

Kindra = 2 x 9 + 2 = 18 + 2 = 20

Kindra has 20 coins.