Answer: E= λ/ 2πε0 with radial direction
Explanation: Using the Gaussian law, we can obtain the Electric at distance r from the line of charge very large.
In this sense
The electric flux by a closed surface is: ∫E.dS= Total charge/ε0
so
at distance r the electric field is constant and surface integral is equal to the curved surface of the cilindrical Gaussian surface around the line of charge. It was used to conduct the Gaussian Law.
this means
A= 2πr L where L is lengt of line of charge
Finally E*2 πr L = λL/ε0
Fron this expression the electric is: E= λ/ 2πε0