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A plane cruising at 233 m/s accelerates at 17 m/s 2 for 4.8 s. What is its final velocity? Answer in units of m/s. 013 (part 2 of 2) 10.0 points How far will it have traveled in that time? Answer in units of m.

User Moujtahed
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1 Answer

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Answer:

Final velocity will be 314.6 m/sec

Distance traveled = 1314.24 m

Step-by-step explanation:

We have given initial velocity u = 233 m/sec

Acceleration
a=17m/sec^2

Time t = 4.8 sec

From first equation of motion
v=u+at, here v is final velocity, u is initial velocity and t is time

So
v=233+17* 4.8=314.6m/sec

Now we have to find distance traveled

From second equation of motion


S=ut+(1)/(2)at^2=233* 4.8+(1)/(2)* 17* 4.8^2=1314.24m

So distance traveled in given time will be 1314.24 m

User Pouriya
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