13.4k views
5 votes
A car makes a trip due north for three-fourths of the time and due south one-fourth of the time. The average northward velocity has a magnitude of 35 m/s, and the average southward velocity has a magnitude of 41 m/s. Taking northward to be the positive direction, what is the average velocity for the trip?

User KorHosik
by
8.0k points

1 Answer

3 votes

Answer:16 m/s

Step-by-step explanation:

Given

Car trip to north for three-fourth of the time

and due to south one-fourth of time

Average northwards velocity is 35 m/s

Average southwards velocity is 41 m/s

Suppose car has moved first in north direction for
(3t)/(4) time with 35 m/s

Distance traveled
=(105t)/(4) m

Now car starts moving in south thus

Distance traveled
=(41t)/(4) m

Therefore net displacement is
=(105t)/(4)-(41t)/(4)=(64t)/(4)=16t

therefore average velocity
=(Displacement)/(Time)


V_(avg)=(16t)/(t)=16 m/s

User Dtorgo
by
7.6k points