Question

A car makes a trip due north for three-fourths of the time and due south one-fourth of the time. The average northward velocity has a magnitude of 35 m/s, and the average southward velocity has a magnitude of 41 m/s. Taking northward to be the positive direction, what is the average velocity for the trip?

Answer 1

Answer:16 m/s

Step-by-step explanation:

Given

Car trip to north for three-fourth of the time

and due to south one-fourth of time

Average northwards velocity is 35 m/s

Average southwards velocity is 41 m/s

Suppose car has moved first in north direction for
`(3t)/(4)` time with 35 m/s

Distance traveled
`=(105t)/(4) m`

Now car starts moving in south thus

Distance traveled
`=(41t)/(4) m`

Therefore net displacement is
`=(105t)/(4)-(41t)/(4)=(64t)/(4)=16t`

therefore average velocity
`=(Displacement)/(Time)`

`V_(avg)=(16t)/(t)=16 m/s`