Question

During a baseball game, a batter hits a high

pop-up.

If the ball remains in the air for 5.47 s, how

high does it rise? The acceleration of gravity

is 9.8 m/s.

Answer in units of m.

Answer 1

The maximum height of the ball is 36.65 m.

Step-by-step explanation:

Given that,

Time = 5.47 sec

The ball must be at top point in half of total time.

We need to calculate the height

Using equation of motion

`s = ut+(1)/(2)gt^2`

Where, s = height

u = initial velocity

g = acceleration due to gravity

Put the value in the equation

`s=0+(1)/(2)*9.8*((5.47)/(2))^2`

`s=36.65\ m`

Hence, The maximum height of the ball is 36.65 m.