Question

Identify the x- and y-intercepts of the equation
4x - y = 8

Answer 1

x = (2,0)

y = (0,-8)

Explanation:

Remember than an intercept always has the other number as 0.

Let's put this in standard form of a linear equation, or y = mx + b

4x - y = 8

-y = -4x + 8

y = 4x - 8

"b" is the y intercept. The y intercept is -8, or (0,-8)

Now, to find the x intercept, all we have to do is substitute 0 for y.

0 = 4x -8

8 = 4x

2 = x

The x intercept is 2, or (2,0)

Answer 2

`\boxed{\boxed{\pink{\sf \leadsto The \ x - intercept \ is \ (2,0) \ \& \ the \ y \ intercept \ is \ (-8,0) }}}`

Explanation:

A linear equation is given to us and we are required to find x and y Intercepts to it. So the given linear equation to us is ,

`\bf \implies 4x - y = 8 \\\\\bf\implies (1)/(8) \bigg( 4x -y\bigg) =(1)/(8)* 8 \\\\\bf\implies (4x)/(8)-(y)/(8) = (8)/(8) \\\\\bf\implies (x)/(2)-(y)/(8)=1 \\\\\bf\implies\boxed{\red{\bf (x)/(2)+(y)/(-8)=1 }}`

Hence on comparing to standard form we get

• x intercept as (2 , 0 )
• y intercept as (0,-8)

Hence the x - intercept is ( 2 , 0 ) and the y - intercept is ( 0 , -8 ) .