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What is the equation of the line that passes through (0-2) and has a slope of 0?

y2
y2
X2

User Nathan Lee
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1 Answer

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\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{-2})~\hspace{10em} \stackrel{slope}{m}\implies 0 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-2)}=\stackrel{m}{0}(x-\stackrel{x_1}{0})\implies y+2=0\implies y=-2

User Sangheestyle
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