Question

If 10.88 moles of NH3 were produced, how many moles of N2 would be
required?

Answer 1

5.44 moles of nitrogen required.

Step-by-step explanation:

Given data:

Number of moles of NH₃ = 10.88 mol

Moles of N₂ required = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Now we will compare the moles nitrogen and hydrogen.

NH₃ : N₂

2 : 1

10.88 : 1/2×10.88 = 5.44mol

5.44 moles of nitrogen required.