Answer:
- a.
![v = 0.0889 (m)/(s)](https://img.qammunity.org/2020/formulas/physics/high-school/dd1k6ewa6mlti3pddzm90xpln0uk5gqkew.png)
- b.
![v = 0.19 (mi)/(hr)](https://img.qammunity.org/2020/formulas/physics/high-school/jnujp38ub00lbxs3b8ixqs0lojnzw5l5em.png)
Step-by-step explanation:
The average speed is :
![v = (distance)/(time)](https://img.qammunity.org/2020/formulas/physics/high-school/nsq4e88gld5l0y0y8btezcoaq8xbg4nf7i.png)
Now, how many seconds are in 10 months? We know that there are 31 days in seven months (January, March, May, July, August and October), 30 days in three months ( April, June and September) and 28 days in February. This gives us:
![days = 31 * 7 + 30 * 3 + 28](https://img.qammunity.org/2020/formulas/physics/high-school/icr2siq1rxk5sikr2gs3arzstil9fru7cd.png)
![days = 335](https://img.qammunity.org/2020/formulas/physics/high-school/ui4r0n5kng7rq2bib5j8f1s2qco4wd39ss.png)
Now, in every day there are 24 hours. So, the total number of hours will be:
![time = 335 \ days * (24 \ hours)/(1 \ day)](https://img.qammunity.org/2020/formulas/physics/high-school/jt3685g9pak54mrvt5bp8bmpfpdueicu2i.png)
![time = 8040 hours](https://img.qammunity.org/2020/formulas/physics/high-school/dz0925khu2pdwi18bhop4wlj9in0slx2pa.png)
So, the speed will be:
![v= (1600 \ mi)/(8040 \ hr)](https://img.qammunity.org/2020/formulas/physics/high-school/rkj6wg511u24gidi2m4x2f7fu51t1qysdq.png)
![v = 0.199 (mi)/(hr)](https://img.qammunity.org/2020/formulas/physics/high-school/6st6sepn5nxbsmaim7lvrps8h7kbcvyh0v.png)
To convert this to m/s we can use the conversion factors:
![v = 0.199 (mi)/(hr) * (1 \ hr )/(3600 \ s ) * (1609 \ m)/(1 \ mi)](https://img.qammunity.org/2020/formulas/physics/high-school/d83p5xm1n760mtrf37epv580aodmkg6ml3.png)
![v = 0.0889 (m)/(s)](https://img.qammunity.org/2020/formulas/physics/high-school/dd1k6ewa6mlti3pddzm90xpln0uk5gqkew.png)