Question

Jeremy is riding his bike down a straight road at 3 m/s when he accelerates at a constant rate for 5 seconds until he reaches a speed of 6 m/s. How far did he travel during his acceleration?

Can someone help me please, can you also show your work.

Answer 1

He traveled 22.5 meters during his acceleration

Step-by-step explanation:

Jeremy is riding his bike down a straight road at 3 m/s when he

accelerates at a constant rate

⇒ His initial speed = 3 m/s

He accelerates at a constant rate for 5 seconds

⇒ The time of acceleration = 5 seconds

He reaches a speed of 6 m/s

⇒ His final speed = 6 m/s

We need to find how far he traveled during his acceleration

Lets find his constant acceleration at first

Acceleration is the rate of change in velocity

`a=(v-u)/(t)`, where v is the final velocity , u is the initial velocity

and t is the time of acceleration

⇒
`a=(6-3)/(5)=0.6` m/sec²

Now lets find the distance using the rule
`s=ut+(1)/(2)at^(2)`

where s is the distance

⇒
`s=3(5)+(1)/(2)(0.6)(5)^(2)`

⇒ s = 15 + 7.5 = 22.5

The distance is 22.5 meters

He traveled 22.5 meters during his acceleration