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Can someone help me with these problems?

Can someone help me with these problems?-example-1
User LulzCow
by
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2 Answers

0 votes

Answer:

see explanation

Explanation:

16

Given

sinΘ = -
(√(3) )/(2) , find the related acute angle

Θ =
sin^(-1)(
(√(3) )/(2)) = 60°

Since Θ is in quadrant 4, then

Θ = 360° - 60° = 300°

17

Given secΘ = - 2, then using cosx =
(1)/(secx) , then

cosΘ =
(1)/(-2) = -
(1)/(2), hence

Θ =
cos^(-1)(
(1)/(2) = 60° ← related acute angle

Since Θ is in quadrant 3 then

Θ = 180° + 60° = 240°

User Travenin
by
7.9k points
3 votes

Answer:

The answer to your question is:

a) 240 and 300°

b) 120 and 240°

Explanation:

You can see the right triangle below (sorry for my handwriting)

I suggest you to memorize the right triangles for 30°, 60° and 45°, they will be very useful.

To solve these questions, you need to work with the right triangle of 60°.

a)

Remember that sine Ф = opposite side / hyp

then sine 60 = √3 / 2 the answer is 60 but it is negative so you need to look for these angles in thtethird and forth quadrangles.

third q = 180 + 60 = 240° forth q = 360 - 60 = 300°

b)

Work with the same triangle

sec Ф = hyp / adjacent side

sec 60 = 2 / 1 = 2 the answer is 60°

but as it is negative you have to look for angles in the second and third quadrangle.

They will be 180 -60 = 120° and 180 + 60 = 240°

Can someone help me with these problems?-example-1
User Akhil Penta
by
9.0k points