Question

Given f(x)=2x^3-3x and g(x)=-3x^2+1, what is the value of h(3) where h(x)=(f+g)(x)?

Answer 1

h(3) = 73

Explanation:

The function
`h(x) = f(x) + g(x) = 2x^3 -3x +3x^2 +1 = 2x^3 +3 x^2 -3x+1`

Now since you need to find the value of this new function at the point x=3, replace x by "3" in the expression above and perform the calculation:

`h(3) = 2(3)^3 +3 (3)^2 -3(3)+1=73`