Question

How do i fill out this ICE chart? please help

Answer 1

Answer: You can probably go onto You Tube and find that answer! Just be detailed in your search! Hope this helps!

Step-by-step explanation:

Just Simple Physics :P

Answer 2

Answer : The given chemical reaction is:

`2C_6H_(10)+17O_2\rightarrow 12CO_2+10H_2O`

Initial 0.427 1.41 0 0

Change -2x -17x +12x +10x

Final 0.427-2x 1.41-17x 12x 10x

Explanation :

First we have to calculate the moles of
`C_6H_(10)` and
`O_2`

`\text{Moles of }C_6H_(10)=\frac{\text{Mass of }C_6H_(10)}{\text{Molar mass of }C_6H_(10)}`

Mass of
`C_6H_(10)` = 35 g

Molar mass of
`C_6H_(10)` = 82 g/mol

`\text{Moles of }C_6H_(10)=(35g)/(82g/mol)=0.427mol`

and,

`\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}`

Mass of
`O_2` = 45 g

Molar mass of
`O_2` = 32 g/mol

`\text{Moles of }O_2=(45g)/(32g/mol)=1.41mol`

Now we have to complete the ICE table.

The given chemical reaction is:

`2C_6H_(10)+17O_2\rightarrow 12CO_2+10H_2O`

Initial 0.427 1.41 0 0

Change -2x -17x +12x +10x

Final 0.427-2x 1.41-17x 12x 10x