Question

A plane drops a hamper of medical supplies from a height of 2830 m during a practice run over the ocean. The plane’s horizontal velocity was 106 m/s at the instant the hamper was dropped. What is the magnitude of the overall velocity of the hamper at the instant it strikes the surface of the ocean? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s.

Answer 1

Overall velocity will be 258.27 m/sec

Step-by-step explanation:

We have given height = 2830 m

Acceleration due to gravity
`g=9.81m/sec^2`

Horizontal velocity
`v_x=106m/sec`

From third equation of motion

`v^2=u^2+2gh`

As the hamper is drooped so u=0

`v^2=2gh`

`v=√(2gh)=√(2* 9.8*2830 )=235.516m/sec`

Overall velocity is given by
`v=√(v_x^2+v_y^2)=√(106^2+235.516^2)=258.271m/sec`

So overall velocity will be 258.27 m/sec