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14. A 7 Kg box sits on an incline of 30°, what is the force down the incline?​
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14. A 7 Kg box sits on an incline of 30°, what is the force down the incline?​

User Ribesg
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1 Answer

1 vote

Answer:

Step-by-step explanation:

To know the force down you need to divide the force into two components X parallel with the inclined surface and Y, the perpendicular one.

F= m* g= 7kg*9,8m/s^2= 68.6 N

Fy= F*cos(30) = - N

Fx= F*sen(30)

N = normal. Force which is perpendicular to the movement equal and opposite to weigh in the plane.

Friction force = Fr= Coef *N

In the inclined there're Fx to one side and Fr to the other side. Perpendicular to it there are Fy and N

User Morothar
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