Time required : 25.876 s
Further explanation
Given
A car weight = 25000 N
Brake force = 628 N
vo= 6.5 m/s
vt = 0(stop)
Required
time to stop
Solution
W = m . g
25000 = m.10
m=2500 kg
Newton's second law
F = m . a
628 = 2500 . a
![\tt a=(628)/(2500)=0.2512~m/s^2](https://img.qammunity.org/2022/formulas/physics/college/qtz3tbpzrt14n6akynpdelze8jt64srxuc.png)
vt=vo-at(deceleration a=-)
0=6.5-0.2512.t
0.2512.t=6.5
t=25.876 s