Answer:The number of seconds after rocket is released
Explanation:
Given
The height of a rocket after it is released is modeled by
![h\left ( t\right )=-16t^2+32t+10](https://img.qammunity.org/2020/formulas/mathematics/college/m9t2dhiqmn0a5s7792w0xbqy7b25k6u2s6.png)
Here t represent the number of seconds after the rocket is released.
Initial velocity can also be determined by this equation by differentiating the
w.r.t time
![\frac{\mathrm{d}h(t)}{\mathrm{d} t}=-32t+32](https://img.qammunity.org/2020/formulas/mathematics/college/j0f8jbpv9e1m6ec8dmziobl9hv8lo00svz.png)
at t=o
![\frac{\mathrm{d}h(t)}{\mathrm{d} t}=32](https://img.qammunity.org/2020/formulas/mathematics/college/kn8l9as4rtqmu2bdhn54yx1lvez3wtr3ih.png)
thus initial velocity will be 32 units/s