Answer:
The horizontal asymptote can be described by the line y = 6
The vertical asymptote can be described by the line x = -2
Explanation:
* Lets the meaning of vertical and horizontal asymptotes
- Vertical asymptotes are vertical lines which correspond to the zeroes
of the denominator of a rational function
- A horizontal asymptote is a y-value on a graph which a function
approaches but does not actually reach
- If the degree of the numerator is less than the degree of the
denominator, then there is a horizontal asymptote at y = 0
- If the degree of the numerator is greater than the degree of the
denominator, then there is no horizontal asymptote
- If the degree of the numerator is equal the degree of the denominator,
then there is a horizontal asymptote at y = leading coefficient of the
numerator ÷ leading coefficient of the denominator
* Lets solve the problem
∵
![f(x)=(6x)/(x+2)](https://img.qammunity.org/2020/formulas/mathematics/college/xr8x2rufp8xa2tsxvcjki9bapx5ulzf8e8.png)
∵ The numerator is 6x
∵ The denominator is x + 2
∴ The numerator and the denominator have same degree
∵ The leading coefficient of the numerator is 6
∵ The leading coefficient of the denominator is 1
∴ There is a horizontal asymptote at y = 6/1
∴ The horizontal asymptote can be described by the line y = 6
- Put the denominator equal zero to find its zeroes
∵ The denominator is x + 2
∴ x + 2 = 0
- Subtract 2 from both sides
∴ x = -2
∴ The vertical asymptote can be described by the line x = -2