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How many moles of methane are in 7.31*10^25 molecules?

User Thatmarvin
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1 Answer

7 votes

Answer:

121 mol CH₄

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Organic

  • Writing chemical compounds
  • Writing organic structures
  • Prefixes
  • Alkanes, Alkenes, Alkynes

Atomic Structure

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Step-by-step explanation:

Step 1: Define

7.31 × 10²⁵ molecules CH₄

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert


\displaystyle 7.31 \cdot 10^(25) \ molecules \ CH_4((1 \ mol \ CH_4)/(6.022 \cdot 10^(23) \ molecules \ CH_4) ) = 121.388 \ mol \ CH_4

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

121.388 mol CH₄ ≈ 121 mol CH₄

User Scrubbie
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