Answer:
Option 1.
Explanation:
The given equation is
![9^{(1)/(3)}=\sqrt[3]{9}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yu55l277galo5s12qrrxhrazbefi75ddyw.png)
We need to find the equation which justifies the given equation.
Taking cube on both sides.
![(9^{(1)/(3)})^3=(\sqrt[3]{9})^3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w0s5repc12n7jkzji8pu0yjoc6ijr6x92c.png)
![(9^{(1)/(3)})^3=9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/39a8i67fzp49tiw2fxwu2aebfvnlbltjwj.png)
Taking LHS,
![LHS=(9^{(1)/(3)})^3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yvb7k88g61s4g96aov638qpxde9mmsasz3.png)
Using power property of exponents.
![[\because (a^m)^n=a^(mn)]](https://img.qammunity.org/2020/formulas/mathematics/middle-school/szk6cyxjbwli8sw7h22ardwfk55yjnha0d.png)
![LHS=9^{(3)/(3)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g5gu2gavkqyi9l5bwob265il2j3dd6rsoa.png)
![LHS=9^(1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ljxibu7ut65x9kv8211eeclruj016i5w0u.png)
![LHS=9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zulutzhpljhjdncglsg0ad6eug6uwe8gdu.png)
![LHS=RHS](https://img.qammunity.org/2020/formulas/mathematics/middle-school/et2d9ww7vn2721d3uztab8kj0w4xcrrqeu.png)
The required equation is
![(9^{(1)/(3)})^3=9^{(1)/(3)* 3}=9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3lhti4ndhd1jt1czwc6dqilm4eye7myuc8.png)
"Nine to the one third power all raised to the third power equals nine raised to the one third times three power equals nine".
Therefore, the correct option is 1.