Question

Solve the following radical equation. 2√x+2-√x-3=√x+9

Answer 1

Explanation:

`2√(x+2) -√(x-3) =√(x+9 )  \\squaring ~both~sides\\4(x+2)+(x-3)-4√((x+2)(x-3)) =x+9 \\4x+8+x-3-x-9=4√(x^2-x-6) \\4x-4=4√(x^2-x-6) \\or ~√(x^2-x-6) =x-1\\again ~squaring\\x^2-x-6=x^2-2x+1\\2x-x=1+6\\x=7`