Question

chapter 3 probability add and mult With one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the entire batch is accepted if every item in the sample is okay. The ABC Electronics Company has just manufactured 2100 write-rewrite CDs, and 160 are defective. If 5 of these CDs are randomly selected for testing, what is the probability that the entire batch will be accepted? Rounded to four decimal place accuracy.

Answer 1

The probability that the entire batch will be accepted is 67.25%

Explanation:

First, knowing that there are 160 defective CDs, we can calculate the probability that taking only one CD, it is not defective:

Total - Defective = Okay

2100 - 160 = 1940

`(1940)/(2100)=0.9238` (92.38%)

Then, in the same way, we calculate the probability if we take 5 CD's of the sample, taking into account that every time I take out one I will have one less in the total, and also one less that is Okay:

`(1940)/(2100) *(1939)/(2099) *(1938)/(2098) *(1937)/(2097) *(1936)/(2096) =0.6725` (67.25%)