Question

what is an equation of the line that passes through the point (-6,-1) and is perpendicular to the line 6x-y=7? (has to be in y=mx+b form)

Answer 1

y =
`-(1)/(6)` x - 2

Explanation:

Slopes of perpendicular lines are opposite reciprocals.

If AB ⊥ CD , then
`m_(AB)`
`m_(CD)` = - 1

y -
`y_(1)` = m(x -
`x_(1)`)

~~~~~~~~~~~

6x - y = 7 ⇔ y = 6x - 7

Slope of given line is 6

Slope of a perpendicular line is
`-(1)/(6)`

( - 6, - 1 )

y + 1 =
`-(1)/(6)` (x + 6)

y =
`-(1)/(6)` x - 2