Answer:
Ans => C => 43.3%
Step-by-step explanation:
2CO + O₂ => 2CO₂
Given 1g CO = 1g/28g·mol⁻¹ = 0.036 mol CO
b/c coefficient of CO = coefficient of CO₂ => moles CO₂ = 0.036 mol = 0.036mol x 44g/mol = 1.57 gCO₂ (theoretical yield)
%Yield = (actual yield/theoretical yield) x 100% = (0.68g/1.57g) x 100% = 43.3%