Final answer:
The boiling point of propanamide is higher than that of N,N−dimethylformamide due to the presence of hydrogen bonding and increased branching in propanamide, resulting in stronger intermolecular forces.
Step-by-step explanation:
The boiling point of propanamide, CH3CH2CONH2, is considerably higher than the boiling point of N,N−dimethylformamide, HCON(CH3)2, even though both compounds are isomeric amides. The higher boiling point can be attributed to the presence of hydrogen bonding in propanamide, which is absent in N,N−dimethylformamide. Hydrogen bonding is a strong intermolecular force that requires more energy to break, leading to a higher boiling point. In addition, the branching of propanamide plays a role in increasing its boiling point, as increased branching results in a more compact molecule with stronger intermolecular interactions. Therefore, the correct answer is that CH3CH2CONH2 has weaker intermolecular forces than HCON(CH3)2.