Question

What is the solutions to the quadratic equation (2b+3)^2=12

Answer 1

Step-by-step explanation:do idk

Answer 2

The solution to the quadratic equation
`(2 b+3)^(2)=12` is
`\bold{4 b^(2)+12 b-3=0}`

Solution:

Using the square of summation algebraic expansion formula for polynomials,

`(x+y)^(2)=x^(2)+y^(2)+2 x y`

Applying the formula on
`(2 b+3)^(2)`

Here
`x = 2b\ and\ y = 3`

Hence
`(2 b+3)^(2)` can be written as
`(2 b)^(2)+(3)^(2)+(2 * 2 b * 3)=12`

On simplification,

`\begin{array}{c}{4 b^(2)+9+(2 * 6 b)=12} \\ {4 b^(2)+9+12 b=12}\end{array}`

On moving 12 from right hand side to left hand side, it becomes negative (-12)

`4 b^(2)+9+12 b-12=0`

Rearranging the terms,
`4 b^(2)+12 b+9-12 = 0`

Subtract 9 from -12, we get
`4 b^(2)+12 b-3 = 0`