Question

An analytical chemist is titrating of a solution of propionic acid with a solution of . The of propionic acid is . Calculate the pH of the acid solution after the chemist has added of the solution to it.

Answer 1

Heres my attempt at this and hope it helps friend

.1372L * (.83M/L) = .114 mols propanoic acid

.06862L * (1.1M/L) = 0.0755 mols NaOH

using the henderson hasselbach equation

ph = pKa + log([A-]/[HA])

so

ph = 4.89 + log(.0755/.114) = 4.72

Step-by-step explanation:

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