Question

A message of length 8x106bits is to be sent from host A to host B, routed through 2 packet switches. The transmission capacity of each of the three linksis 2 Mbps. Ignoring propagation, queuing and processing delay, how long will it take to move the message as a single packet from host A to host B assuming each packet switch uses store-and-forward switching

Answer 1

Time from source host to 1st packet switch = 4 secs

Total time = 12 secs

Step-by-step explanation:

Solution:

Message Length =
`8 x 10^(6)` bits

Each link is = 2Mbps

Assumption:

Each packet switch uses store - and - forward switching

So, in order to calculate the total time taken to move the message as a single packet from host A to host B with the above assumption, first we need to calculate the time required to sending message from source host to 1st packet switch.

For that,

we need to divide Length of the message to Transmission capacity of each link.

Time from source host to 1st packet switch = 8/2

Time from source host to 1st packet switch = 4 secs

Now, to calculate the total time taken till the destination = 4 x 3 hops

Total time = 12 secs