21.1k views
0 votes
Please help. 50 points. ​

Please help. 50 points. ​-example-1
User Calise
by
5.4k points

2 Answers

3 votes

50 points, 20 characters

User Grismar
by
5.5k points
4 votes

Answer:

The answer to your question is:

2.-

a) ∠ACB + ∠ ACE = 7x + 54

b) ∠ACB = 115° ∠ ACE = 65°

3.-

a) They measure the same

b) ∠MFG = ∠EFN = 80°

Explanation:

1.- ∠ACB and ∠ ACE are linear pairs so ∠ACB + ∠ ACE = 180

∠ACB = 5x + 25

∠ ACE = 2x + 29

∠ACB + ∠ ACE = 180 = 5x + 25 + 2x + 29

180 = 7x + 54

7x + 54 = 180

7x = 180 -54

7x = 126

x = 126 / 7

x = 18

Then ∠ACB = 5(18) + 25 = 115° ∠ ACE = 2(18) + 29 = 65

2.- ∠MFG ∠EFN are vertical angles

∠MFG = 7x - 18 ∠EFN = 5x + 10

They measure the same, then

7x - 18 = 5x + 10

7x - 5x = 18 + 10

2x = 28

x = 28/2

x = 14

∠MFG = 7(14) - 18 = 98 - 18 = 80 ∠EFN = 5(14) + 10 = 70 + 10 = 80

User Rajendran T
by
5.9k points