Answer:
![C=(\pi)/(R* T)](https://img.qammunity.org/2020/formulas/chemistry/college/aus9q2fzs3cy2zt9gzbvwgoaftlfp27n3r.png)
Explanation:-
Osmotic pressure is a colligative property which depends on the amount of solute added.
![\pi=CRT](https://img.qammunity.org/2020/formulas/chemistry/college/6urp0xucv2gfsxrhr8zo7dw5my1730z4n5.png)
= osmotic pressure = 5.1 atm
C= concentration in Molarity
R= solution constant = 0.0821 Latm/Kmol
T= temperature = 312 K
![C=(\pi)/(R* T)](https://img.qammunity.org/2020/formulas/chemistry/college/aus9q2fzs3cy2zt9gzbvwgoaftlfp27n3r.png)
![C=(5.1atm)/(0.0821Latm/Kmol* 312K)=0.2mol/L](https://img.qammunity.org/2020/formulas/chemistry/college/ika1kcoxt9li6ryrvxcy4u10w41l4vgmt1.png)
Thus the equation for calculating the molarity of this solution is
![C=(\pi)/(R* T)](https://img.qammunity.org/2020/formulas/chemistry/college/aus9q2fzs3cy2zt9gzbvwgoaftlfp27n3r.png)