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The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant R. Suppose the osmotic pressure of a certain solution is measured to be 5.1 atm at an absolute temperature of 312 K. Write an equation that will let you calculate the molarity of this solution. Your equation should contain only symbols. Be sure you define each symbol other than R .

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Answer:
C=(\pi)/(R* T)

Explanation:-

Osmotic pressure is a colligative property which depends on the amount of solute added.


\pi=CRT


\pi = osmotic pressure = 5.1 atm

C= concentration in Molarity

R= solution constant = 0.0821 Latm/Kmol

T= temperature = 312 K


C=(\pi)/(R* T)


C=(5.1atm)/(0.0821Latm/Kmol* 312K)=0.2mol/L

Thus the equation for calculating the molarity of this solution is
C=(\pi)/(R* T)

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