Question

Use Phythagoras Theorem!!

the length pf a rectangle is 50 cm and its diagonal is 51 cm. work out the area of the rectangle, to the nearest square centimetre.​

Answer 1

Answer: Area of the rectangle = 102.5 cm² Round to 103 cm²

Explanation:

The diagonal is the hypotenuse, c So subtract the square on the base (length) to find the altitude (height).

a² + b² = c²

a² + 50² = 51²

a² = 51² - 50²

a² = 2601 -2500

a² = 101 take the square root of both sides

a = √101

a = 10.04987562 Round to 10.05

Area = LW

Area = 50 × 10.05

Area = 102.5 cm² Round to 103 cm²

Answer 2

a² + b² = c²

50² + 51² = c²

2500 + 2601 = c²

5101 = c²

√5101 ≈ 71.42 cm.