Answer:
q=2313.04

T=690.86°C
Step-by-step explanation:
Given that
Thickness t= 20 cm
Thermal conductivity of firebrick= 1.6 W/m.K
Thermal conductivity of structural brick= 0.7 W/m.K
Inner temperature of firebrick=980°C
Outer temperature of structural brick =30°C
We know that thermal resistance

These are connect in series

Heat transfer

So heat flux
q=2313.04

Lets temperature between interface is T
Now by equating heat in both bricks

So T=690.86°C