Question

a car headed north at 15 m/s accelerates for 4.25 s to reach a velocity of 28.3 m/s. What is the acceleration of the car?

Answer 1

The acceleration of the car is
`3.13 m/s^2`

Step-by-step explanation:

In the question it is given that car initially heads north with a velocity
`15 m/s`. It then accelerates for
`4.25 s` and in the end its velocity is
`28.3 m/s`.

initial velocity
`u = 15 m/s`

time
`t=4.25 s`

final velocity
`v=28.3 m/s`

The equation of acceleration is

`a= ((v-u))/(t)`

`= ((28.3-15))/(4.25) =  \frac {13.3}{4.25} =3.13m/s^2`

The value of acceleration is positive, here since the car is speeding up. If it was slowing down the value of acceleration would be negative.