Question

What are the solutions to the equation 4x^3 =36x

Answer 1

The answer to your question is:

x₁ = 0

x₂ = -3

x₃ = 3

Explanation:

Equation 4x³ = 36 x

Process

4x³ - 36x = 0

4x (x² - 9) = 0

4x (x + 3)(x - 3) = 0

Finally

4x = 0 x + 3 = 0 x -3 = 0

x = 0/4 x₂ = -3 x₃ = 3

x₁ = 0

Answer 2

`x=0\text{ or }x=-3\text{ or }x=3`

Explanation:

We have been an equation
`4x^3=36x`. We are asked to find the solutions for our given equation.

First of all, we will subtract
`36x` from both sides as:

`4x^3-36x=36x-36x`

`4x^3-36x=0`

Let us factor the given equation.

`4x(x^2-9)=0`

Use difference of squares:

`4x(x^2-3^2)=0`

`4x(x+3)(x-3)=0`

Using zero product property, we will get:

`4x=0\text{ or }(x+3)=0\text{ or }(x-3)=0`

`x=0\text{ or }x=-3\text{ or }x=3`

Therefore, the solutions for our given equation would be
`x=0\text{ or }x=-3\text{ or }x=3`.