Answer:
The oxidation state is +3.
chemical formula of compound is Cr₂(SO₄)₃.
Step-by-step explanation:
Calculation of oxidation state:
Cr₂(SO₄)₃
Cr= ?
The oxidation state of SO₄ = -2
2x + 3( -2) = 0
2x - 6 = 0
2x = 6
x = 6/2
x= 3
The oxidation state of Cr is +3.
The Cr has valency of 3 so three SO₄ will require while the valency of SO₄ is 2 so two Cr will require.
Cr×2 and SO₄×3
Cr₂(SO₄)₃
we know that oxidation state of Cr is +3 so (3×2) = 6
and the oxidation state of SO₄ is -2 so (-2× 3) = -6
6-6= 0
The overall charge is 0, the compound will be neutral.