Question

Can someone please help me out on these few questions?

Answer 1

For the 3rd picture, the answer is 21x^2.

Explanation:

Well, on the top row, you have 7
`x^(2)` times 3. That's 21
`x^(2)`. So, for the second row, it's the same thing. And, 7*3=21 and you have
`x^(2)` left over. So, 21+
`x^(2)` = 21
`x^(2)`

Hope this helped you out! (:

Answer 2

See Below

Explanation:

1.

`(2m+4)^(2) \\= (2m + 4)(2m + 4) \\= (2m)(2m) + (4)(2m) + (2m)(4) + (4)(4) \\= 4m^(2) + 8m + 8 m + 16 \\= 4m^(2) + 16m + 16\\`

2.

`(2x + 1)( x - 3) \\= (2x)(x) + (1)(x) + (2x)(-3) + (1)(-3) \\= 2x^(2) + x - 6x -3 \\= 2x^(2) -5x -3`

3. The missing term is 7x^2 * 3

`(7x^(2))(3)\\= 21x^(2)`

4. The terms in the final polynomial are 42x^2, 9 and 42x^4. Because the missing term is 21x^2 and the terms in the final polynomial includes all the blocks