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When a process is in control, it results in there being, on average, 16 defects per unit of output. c-chart limits of 8 and 24 would lead to a

User Mrpbody
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1 Answer

5 votes

Answer:

4.56%

Step-by-step explanation:

From the given information:

In a c-chart limit

UCL =
\bar c+ z * √(\bar c )

where;


\bar c = 16

UCL = 24

Then:


24 = 16 + z * √(24)


24 -1 6 = z * √(24)


8 = z * 4.89


z = (8)/(4.89)

z
\simeq 2.0

At z = 2.0, the value represents the probability of 95.44% of not making a Type 1 error.

This implies that the probability of making a Type 1 error = 1 - 95.44%

= 4.56%

User Yaqoob
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