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Select the graph of the equation below.
y= -1/4x^2+1

Select the graph of the equation below. y= -1/4x^2+1-example-1
Select the graph of the equation below. y= -1/4x^2+1-example-1
Select the graph of the equation below. y= -1/4x^2+1-example-2
User Nsbm
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1 Answer

1 vote

Answer:

a.

Explanation:

Since you have the different parabolas there, the simplest way to determine which one is, is replacing x as 0 and then y as 0

y = -1/4x^2 + 1

When x = 0

y = -1/4 (0)^2 +1 = 1

When y = 0

0 = -1/4x^2 +1

1/4 x^2 = 1

x^2 = 4

x = + 2

x = - 2

The parabola with points:

(0,1); (-2,0) and (2,0) is a.

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