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Help please? Mathematics

Help please? Mathematics-example-1

1 Answer

3 votes

Answer: (7) 6.9% (8) Policy B (9) Policy B

(10) 480 miles per hour (11) 275 miles (12) 318.9 miles

Explanation:

7)

Policy A Total = $334 least expensive policy

Policy B Total = $357

Policy C Total = $338 most expensive policy


(357-334)/(334)\quad =(23)/(334)\quad =0.0688\quad =\large\boxed{6.9\%}

8)


\frac{\text{Policy A Liability}}{\text{Policy A Total}}=(157)/(334)\quad =0.470\quad =47.0\%\\\\\\\frac{\text{Policy B Liability}}{\text{Policy B Total}}=(152)/(357)\quad =0.426\quad =42.6\%\\\\\\\frac{\text{Policy C Liability}}{\text{Policy C Total}}=(160)/(338)\quad =0.473\quad =47.3\%

The lowest percent is Policy B

9)

Policy A = 297

Policy B = 309 most expensive policy

Policy C = 306

The most expensive policy is Policy B

10) d = r × t

2160 = r(4.5)

÷4.5 ÷4.5

480 = r

11) Car 1 and Car 2 create a straight line in opposite directions

Car 1 distance + Car 2 distance = Total distance

35 mph (4 hrs) + 45 mph (3 hrs) = Total distance

140 miles + 135 miles = Total distance

275 miles = Total distance

12) Train 1 and Train 2 create a right triangle - use Pythagorean Theorem


(Train \ 1)^2+(Train\ 2)^2=distance^2\\\\. [60\ mph(4\ hrs)]^2 +[70\ mph(3\ hrs)]^2=distance^2\\\\.\qquad 57,600\quad \quad \quad +\qquad 44,100\qquad =distance^2\\\\.\qquad \qquad \qquad 101,700\qquad \qquad \qquad \quad = distance^2\\\\.\qquad \qquad \qquad \large\boxed{318.9\ miles}\quad =distance

User Ewout Graswinckel
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