Answer:
0
Explanation:
So we are looking for a hole since the limit exists and f(b) doesn't exist/at least not equal to the limit.
The hole is at x=0 so b=0.
This would make the limit at x=0 be 2 which does exist.
Also f(0)=1 which does exist.
However 1 is not 2 which means the function in not continuous at x=b=0.
For it to be continuous:
You have to have the limit exist at x=b.
You also have to have f(b) exists.
You have have the limit at x=b is equal to f(b).
So parts 1 and 2 passes here, but the last part we did not get a pass which is what we wanted because we were looking for a discontinuity where the limit existed while the function was not continuous there which meant we needed either 2 or 3 had to fail.