Answer:
Explanation:
When two fair dice are tossed sample space consists of 36 events
(1,1)....(6,6)
A_ The difference of numbers is 2 or less
Favorable outcomes =

Hence Probability =

B) A 4 does not appear on either die
Then we must not have these

Hence probability =

C: The sum of numbers is 10 or more:
FAvourable outcomes are:

Probability =
