(h + k)(2) = 5
(h - k)(3) = 9
evaluate 3h(2) + 2k(3) = 17
Answer: 5
Explanation:
Given h(x) = x²+1 and k(x) = x-2
h(x)+k(x) = (x²+1)+(x-2)
h(x)+k(x) = x²+x-1
To get (h+k)(2), we will substitute x=2 into the resulting function to give
(h+k)(2) = 2²+2-1
(h+k)(2) = 6-1
(h+k)(2) = 5
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