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A shopper pushes a cart 50 m south down one aisle and then turns 90.0° west and moves 23 m. He then makes another 90.0° turn and moves 14 m. (a) What is the largest possible displacement of the shopper? m ° counterclockwise from west (b) What is the smallest possible displacement of the shopper? m ° counterclockwise from west

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Answer:

Explanation:

Given

Shopper pushes a cart 50 m south down then turns 90 ^{\circ} west and moves 23 m.

he then makes
90^(\circ) turn and moves 14 m

(a)Largest possible displacement is when he turns towards south

Net displacement
=√(64^2+23^2)=68.0 m

(b)Smallest displacement when he turns towards north


=√(36^2+23^2)


=√(1825)=42.72 m

A shopper pushes a cart 50 m south down one aisle and then turns 90.0° west and moves-example-1
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