Question

A and B are points on a line that has the slope 2. The abscissa of B exceeds the abscissa of A by 3.5. State the relationship of the ordinate of B to the ordinate of A.

Answer 1

The ordinate of B exceeds the ordinate of A by 7

Explanation:

Let

A(x1,y1),B(x2,y2)

where

x1 is the abscissa of A

x2 is the abscissa of B

y1 is the ordinate of A

y2 is the ordinate of B

we know that

`m=(y2-y1)/(x2-x1)`

`m=2`

so

`2=(y2-y1)/(x2-x1)` -----> equation A

`x2=x1+3.5` ----> equation B

substitute equation B in equation A

`2=(y2-y1)/(x1+3.5-x1)`

`2=(y2-y1)/(3.5)`

`7=y2-y1`

`y2=y1+7`

therefore

The ordinate of B exceeds the ordinate of A by 7