Question

1. If m< 1 = 7x + 6 and m2 2 = 8x – 6, find the value of x so that p is
perpendicular to q.

Answer 1

7x + 6 =8x - 6

x= 12

Explanation:

1. put them equal to each other
2. then subtract 8x from both sides

• 7x(-8x) + 6 = 8x(-8x) - 6

1. to get -1x

• -1x + 6 = -6

1. then subtract 6 from both sides

• -1x +6(-6) = -6(-6)

1. you'll get -1x = -12
2. then divide -1 to both sides

• -1x/-1 = -12/-1

1. then you get x = 12