Question

A parachutist descending at a speed of 14.8 m/s loses a shoe at an altitude of 55.1 m. What is the speed of the shoe just before it hits the ground? The acceleration due to gravity is 9.81 m/s 2 . Answer in units of m/s.

Answer 1

v = 36.05 m/s

Step-by-step explanation:

It is given that,

Initial speed of the parachutist, u = 14.8 m/s

Altitude, h = 55.1 m

The acceleration due to gravity,
`a=9.81\ m/s^2`

Let v is the speed of the shoe just before it hits the ground. The third equation of motion is given by :

`v^2=u^2+2ah`

`v^2=(14.8)^2+2* 9.81* 55.1`

v = 36.05 m/s

So, the speed of the show just before it hits the ground is 36.05 m/s. Hence, this is the required solution.