Answer:
Part b)
h = 78.5 m
Part c)
v = 39.24 m/s
Step-by-step explanation:
Part b)
If ball need t = 0 to t = 4 s then height of the tower is the total displacement of the ball in t = 4 s interval
here if ball start from rest
then its displacement is given as



Part c)
Speed of the bearing at the end of the motion of the ball


